(a) N 2F2 (F~N~N~F)
(b) PF 3
(c) O 3 (O~O~O)
(d) XeF 4
(e) NO
(f) BeCl 2
(g) SF 4
a)
b)
c)
d)
e) all of the above
H
2C=CH2 + Cl2
--> ClH2C-CH2Cl
(each C atom is bonded to two H atoms and one Cl atom, and then attached
to the other C atom)
D C-H = 413 kJ/mol
D C-C = 347 kJ/mol
D C=C = 614 kJ/mol
D C-Cl = 339 kJ/mol
D Cl-Cl = 239 kJ/mol
a) -172 kJ
b) -344 kJ
c) 172 kJ
d) 344 kJ
e) 167 kJ
H
2C=CH2 + H2O
--> CH3CH2OH
D C-H = 413 kJ/mol
D C-C = 347 kJ/mol
D C=C = 614 kJ/mol
D C-O = 358 kJ/mol
D O-H = 463 kJ/mol
a) Yes
b) No
a)
true
b) false
a)
b)
c)
d)
e)
a)
sp, sp2, sp3
b) sp2, sp 3, sp3
c) sp3, sp 3, sp3
d) sp3, sp 3d, sp3d
2
e) sp3d 2 , sp3d
2 , sp3d2
a)
Bonds between oxygen and hydrogen atoms form as the result of orbital
overlap.
b) Hydrogen atoms need to undergo hybridization
c) Oxygen utilizes sp
3
hybrid orbitals to form bonds with hydrogen and to house lone pairs
of electrons.
d) Orbitals are hybridized in order to form a degenerate
orbital set from a number of non-degenerate atomic orbitals.
e) The number of hybrid orbitals equals the number
of atomic orbitals that enter the hybridization.