(CN of cation) x (stoichiometric coefficient of cation) = (CN of anion) x (stoich. coeff. of anion)
So, for example, in the rutile (TiO2) structure, the cations are octahedral, so
6 x 1 = (CN of oxygen) x 2, and therefore CN of oxygen must be 3.
Things to note about PbTiO3: (a) It has the basic structure of ReO3, with big Pb2+ ions filling the holes. BUT... (b) The boxes are not symmetrical any more. The vertical TiO distances are not all the same: you can think of the Ti atoms as all being shifted in one direction. (This loss of symmetry is very important for possible practical applications of PbTiO3, such as new types of computer memory.)
Things to note about "1-2-3": (a) It has the basic structure of ReO3, with Ba2+ (yellow) and Y3+ (pink) ions filling the holes between the Cux+ (brown) and O2– (red). BUT... (b) The boxes are not all the same. Partly this is because some have Ba2+ (yellow) in the center and some have Y3+ (pink). The boxes with Y3+ in the center are smaller, as you might expect because Y3+ is smaller than Ba2+. (c) Someof the O atoms are "missing"! That is, some edges have no O atoms in places where the ReO3 and PbTiO3 structures would have O atoms. This is required by the stoichiometry of the compound, YBa2Cu3O7 (otherwise it would be YBa2Cu3O9). It also allows some of the Cu ions to be square-planar rather than octahedral. (d) What is the oxidation state of Cu in this structure?
This structure contains oxide ions in an approx. hexagonal close-packed arrangement. The gray Al3+ ions are in octahedral sites, but because of the formula, only 2/3 of the cation sites are occupied.
This is a complicated structure, so please concentrate on the following: (a) the overall cubic symmetry; (b) the yellow Fe2+ ions, in tetrahedral sites surrounded by 4 O atoms (red); and (c) the gray Cr3+ ions, in octahedral sites.